When 435 J of heat is added to 3.4 g of olive oil at 21.0oC, the temperature increases to 85oC. What is the specific heat of olive oil?
awencer C
q = mass x specific heat x (T2 - T1)
435 J = 3.4 g x specific heat x (85 - 21)
Solve for specific heat
To find the specific heat of olive oil, we can use the formula:
Q = mcΔT
Where:
Q = heat energy (in Joules)
m = mass (in grams)
c = specific heat (in J/g°C)
ΔT = change in temperature (in °C)
Given:
Q = 435 J
m = 3.4 g
ΔT = 85°C - 21°C = 64°C
Plugging in the values, the formula becomes:
435 J = (3.4 g)(c)(64°C)
To solve for c, divide both sides of the equation by (3.4 g)(64°C):
435 J / [ (3.4 g)(64°C) ] = c
c ≈ 2.01 J/g°C
Therefore, the specific heat of olive oil is approximately 2.01 J/g°C.
To find the specific heat of olive oil, we need to use the formula:
Q = mcΔT
Where:
Q is the amount of heat absorbed or released (in joules)
m is the mass of the substance (in grams)
c is the specific heat of the substance (in J/g°C)
ΔT is the change in temperature (in °C)
In this case, we have the following information:
Q = 435 J
m = 3.4 g
ΔT = (85°C - 21°C) = 64°C
Plugging in the values, we can rearrange the formula to solve for c:
c = Q / (m * ΔT)
Let's calculate it:
c = 435 J / (3.4 g * 64°C)
First, we need to convert grams to kilograms, since the specific heat is typically given in J/g°C:
3.4 g = 3.4 * 10^-3 kg
Now we can substitute the values:
c = 435 J / (3.4 * 10^-3 kg * 64°C)
c = 20,220 J / (0.2176 kg°C)
c ≈ 92.90 J/g°C
Therefore, the specific heat of olive oil is approximately 92.90 J/g°C.