solve the system of linear equations
{2x+3y=4, 4x-6y=20
2x+3y=4
4x-6y=20
double the first:
4x + 6y = 8
4x - 6y = 20
add them:
8x = 28
x = 28/8 = 7/2
sub into the first,
2(7/2) + 3y = 4
7 + 3y = 4
3y = -3
y = -1
thank you that is the correct answer!
To solve the system of linear equations:
Step 1: Choose one of the equations to solve for one variable in terms of the other. Let's solve the first equation for x in terms of y:
2x + 3y = 4
2x = 4 - 3y
x = (4 - 3y) / 2
Step 2: Substitute the expression for x in the second equation:
4x - 6y = 20
4((4 - 3y) / 2) - 6y = 20
2(4 - 3y) - 6y = 20
8 - 6y - 6y = 20
-12y = 12
y = -1
Step 3: Substitute the value of y into either of the original equations to solve for x. Let's use the first equation:
2x + 3(-1) = 4
2x - 3 = 4
2x = 4 + 3
2x = 7
x = 3.5
Therefore, the solution to the system of linear equations is x = 3.5 and y = -1.