# A student holds a water balloon outside of an open window and lets go. The window is 10 meters above the ground, and the balloon is falling under the acceleration of gravity, which is 9.8 m/s^2. There are two equations that can be used to describe its motion over time:

x= x0 + v0t + 1/2 at^2
v= v0 + at
Would the balloon hit the ground before or after 1.0 s of falling? Which equation did you use to decide, and what comparison did you make to determine that it would or would not hit the ground by then?

Use 3 sentences.

Question ID
1878834

11

Created

Rating
1

Views
2,237

## 0 = 10 + 0 - (1/2) (9.81) t^2

4.9 t^2 = 10
t = 1.43 seconds in the air before hitting ground
so
it is still in the air after one second, like period :)

2288681

Created

Rating
4

2288656

Created

Rating
2

## I did yf = y0 + bot + 1/2at^2 (1)

So 0 = 10m 1/2gt^2
Then t = 2 + 10m/9.8/8^2 = 1.4s.

2288657

Created

Rating
2

2288658

Created

Rating
2

2288661

Created

Rating
2

2300429

Created

Rating
2

2288682

Created

Rating
1

2288683

Created

Rating
1

2288793

Created

Rating
1