A dried pea is fired from a plastic drinking straw that has a mass of .50g. If the force exerted on the pea averages 0.4 N over the 0.10 s flight through the straw,
(a) at what speed will the pea emerge?
(b) what was the impulse imparted to the pea?
To find the answers to these questions, we need to use the concepts of force, time, velocity, and impulse.
(a) To find the speed at which the pea will emerge, we can use the equation:
velocity = (force * time) / mass
Given:
Force = 0.4 N
Time = 0.10 s
Mass of the straw = 0.50 g (or 0.0005 kg since 1 g = 0.001 kg)
Substituting these values into the equation:
Velocity = (0.4 N * 0.10 s) / 0.0005 kg
Calculating this equation, we get:
Velocity = 8 m/s
Therefore, the pea will emerge from the straw with a speed of 8 m/s.
(b) To find the impulse imparted to the pea, we can use the equation:
impulse = force * time
Given:
Force = 0.4 N
Time = 0.10 s
Substituting these values into the equation:
Impulse = 0.4 N * 0.10 s
Calculating this equation, we get:
Impulse = 0.04 N·s
Therefore, the impulse imparted to the pea is 0.04 N·s.