Find the number N,such that when one third of it is added to 8, the result is the same as when one second of it is subtracted from 18
N/3 + 8 = 18 - N/2
5/6 N = 10
N = 12
(1/3)n + 8 = 18 - (1/2)n
times 6
2n + 48 = 108 - 3n
5n = 60
etc
" ....one second of it.." usually stated as "... one half of it ..."
To solve this problem, we can set up an equation based on the given information. Let's let 'N' represent the unknown number.
We know that when one third of 'N' is added to 8, the result is the same as when one second (or half) of 'N' is subtracted from 18. Mathematically, this can be written as:
(1/3)N + 8 = 18 - (1/2)N
To find 'N', we need to isolate it on one side of the equation. Let's solve the equation step by step:
(1/3)N + 8 = 18 - (1/2)N
First, let's get rid of the fractions by multiplying the entire equation by the least common denominator of 3 and 2, which is 6:
6 * [(1/3)N + 8] = 6 * [18 - (1/2)N]
2N + 48 = 108 - 3N
Next, let's simplify the equation by combining like terms:
2N + 3N = 108 - 48
5N = 60
Finally, let's solve for 'N' by dividing both sides of the equation by 5:
N = 60 / 5
N = 12
Therefore, the number 'N' is equal to 12.