Set up and solve a proportion for the following application problem. If 3 pounds of grass seed cover 475 square feet, how many pounds are needed for square 5225 feet?
Please Help!!!
To set up and solve a proportion for this application problem, we can use the ratio of pounds of grass seed to square feet. Let's call the unknown pounds of grass seed needed for 5225 square feet as "x".
We can set up the proportion as follows:
3 pounds / 475 square feet = x pounds / 5225 square feet
To solve for x, we can cross-multiply and then solve for x.
3 pounds * 5225 square feet = 475 square feet * x pounds
15,675 pounds * square feet = 475 square feet * x pounds
15,675 = 475x
Next, divide both sides of the equation by 475 to isolate x:
15,675 / 475 = x
x ≈ 32.8947
Therefore, approximately 32.8947 pounds (or rounded to 32.9 pounds) of grass seed would be needed for 5225 square feet.
To solve this application problem, we need to set up and solve a proportion.
First, let's define the given information:
- 3 pounds of grass seed cover 475 square feet.
Now, let's set up the proportion:
The proportion will compare the pounds of grass seed to the square feet.
Let x be the variable that represents the number of pounds needed for 5225 square feet.
The proportion can be set up as follows:
3 pounds / 475 square feet = x pounds / 5225 square feet
This proportion states that the ratio of pounds to square feet is the same for both situations - 3 pounds covering 475 square feet and x pounds covering 5225 square feet.
Now, to solve for x, we can cross-multiply and then divide:
(3 pounds)(5225 square feet) = (475 square feet)(x pounds)
15725 pounds = 475x
To isolate x, divide both sides by 475:
x = 15725 pounds / 475 square feet
Simplifying the right side:
x ≈ 33 pounds
Therefore, approximately 33 pounds of grass seed are needed to cover 5225 square feet.
Remember, when solving these types of application problems, setting up a proportion and cross-multiplying can help you find the unknown value.
3/475 = x/5225
475x = 3*5225
x = 3*5225/475 = .....