The first term of an AP Is 2 and common difference is 3. Find the sum of the first 11 terms.
direct application of your formula:
sum(11) = (11/2)( 2(2) + 10(3) ) = ....
To find the sum of the first 11 terms of an arithmetic progression (AP), you can use the formula:
Sum = (n/2)(2a + (n-1)d)
Where:
- n is the number of terms (11 in this case)
- a is the first term (2 in this case)
- d is the common difference (3 in this case)
Let's substitute the values into the formula:
Sum = (11/2)(2(2) + (11-1)(3))
= (11/2)(4 + 10(3))
= (11/2)(4 + 30)
= (11/2)(34)
= 11(17)
= 187
Therefore, the sum of the first 11 terms of the AP is 187.