Graph the line whose x-intercept is 5 and whose y-intercept is 9
Which unit and lesson?
mark two points
x = 0, y = 9
x = 5, y = 0
draw a line through them
or
Let's find an equation for the line to make it all clear
y= m x + b
when x = 0, it hits the y axis at b = 9
so y = m x + 9
when y = 0, it hits the x axis at x = 5
so
0 = 5m + 9
m = -9/5
so
y = -9/5 x + 9
plot the two intercepts
draw the line through them
for the equation, use the intercept form
x/5 + y/9 = 1
To graph the line that has an x-intercept of 5 and a y-intercept of 9, we can use the slope-intercept form of a linear equation, which is y = mx + b, where m is the slope and b is the y-intercept.
The x-intercept occurs when y = 0, and the given x-intercept is 5. Therefore, we have the point (5,0).
The y-intercept occurs when x = 0, and the given y-intercept is 9. Therefore, we have the point (0,9).
To find the slope of the line, we can use the formula: slope (m) = (change in y) / (change in x).
Using the coordinates of the two points we have, we can calculate the slope as follows:
m = (0 - 9) / (5 - 0) = -9 / 5.
Now that we have the slope and the y-intercept, we can write the equation of the line as y = (-9/5)x + 9.
To graph the line, we plot the x-intercept at (5,0) and the y-intercept at (0,9). Then, we can draw a straight line passing through these two points to represent the given line.