If the molar heat of combustion of ethane (C2H6) is -1560 kJ/mol. The heat produced when 111 g of ethane is burned is a.bc MJ.
I don't understand exactly what you're asking.
molar mass ethane is 30 g/mol so
-1560 kJ x 111/30 = ? kJ.
If you want MJ you divide kJ by 1000.
To find the heat produced when 111 g of ethane is burned, we need to follow these steps:
Step 1: Calculate the number of moles of ethane (C2H6):
We can use the formula:
Number of moles = Mass / Molar mass
The molar mass of C2H6 (ethane) is:
C2H6 = (2 * atomic mass of C) + (6 * atomic mass of H)
= (2 * 12.01 g/mol) + (6 * 1.01 g/mol)
= 24.02 g/mol + 6.06 g/mol
= 30.08 g/mol
Number of moles = 111 g / 30.08 g/mol
≈ 3.683 mol (approximately)
Step 2: Calculate the heat produced:
The molar heat of combustion of ethane is given as -1560 kJ/mol.
To convert the result to MJ (megajoules), we divide by 1000.
Heat produced = Number of moles * Molar heat of combustion
= 3.683 mol *(-1560 kJ/mol)
= -5737.68 kJ
Converting to MJ:
Heat produced = -5737.68 kJ / 1000
≈ -5.738 MJ (approximately)
Therefore, the heat produced when 111 g of ethane is burned is approximately -5.738 MJ.
To calculate the heat produced when burning 111 g of ethane, we need to follow these steps:
Step 1: Calculate the number of moles of ethane.
Molar mass of C2H6 = 2 * atomic mass of carbon + 6 * atomic mass of hydrogen
= (2 * 12.01 g/mol) + (6 * 1.01 g/mol)
= 24.02 g/mol + 6.06 g/mol
= 30.08 g/mol
Number of moles = Mass of ethane / Molar mass
= 111 g / 30.08 g/mol
Step 2: Calculate the heat produced.
Heat produced = Number of moles * Molar heat of combustion
First, let's convert the molar heat of combustion from kJ/mol to J/mol:
Molar heat of combustion = -1560 kJ/mol = -1560000 J/mol
Now we can calculate the heat produced:
Heat produced = (111 g / 30.08 g/mol) * (-1560000 J/mol)
Step 3: Convert the heat produced from Joules (J) to MegaJoules (MJ).
1 MJ = 10^6 J
Heat produced (in J) = Heat produced (in MJ) * 10^6 J/MJ
Finally, we can calculate the heat produced in a.bc MJ by dividing the value obtained in Step 3 by 10^6 and rounding to the desired decimal places.