The third and seventh terms of an ap are respectively -2 and 10 find the value of the first term and number of term which must be add to give sum of 410

Where is the answer

Where is the working

Am asking the same question

Tn = a + (n-1) d

so for example T3 = a + 2 d and T7 = a + 6 d
that gives you two linear equations to solve for a and d
then use the equation for sum of terms to find the n for sum of 410

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Math is Fun arithmetic sequence

a+2d = -2

a+6d = 10
solve for a and d, and then you have
n/2 (2a+(n-1)d) = 410
Since you now know a and d, just use them to solve for n

I am not about to do it for you. It is pure plug and chug.