Robins eat 16 worms in the morning on an average sunny day. On rainy days, robins average 4 fewer worms in a morning. Last week, there were 3 sunny days and 4 rainy days. How many worms did a robin eat that week?
4*12 + 3*16
= 48 + 48
= 96
ye its 96
Yes, that's correct! The robin ate a total of 96 worms last week.
To find out how many worms a robin ate last week, we need to calculate the total number of worms eaten on sunny days and rainy days separately, and then add them together.
On an average sunny day, a robin eats 16 worms. So, on 3 sunny days, the robin would have eaten:
Total worms on sunny days = 16 worms/day * 3 days = 48 worms.
On a rainy day, a robin eats 4 fewer worms than on a sunny day. So, the number of worms eaten on a rainy day is:
Worms on rainy day = 16 worms - 4 worms = 12 worms.
Since there were 4 rainy days in the last week, the robin would have eaten:
Total worms on rainy days = 12 worms/day * 4 days = 48 worms.
Now, to find the total number of worms eaten last week, we add the number of worms on sunny days and rainy days:
Total worms eaten = Total worms on sunny days + Total worms on rainy days
= 48 worms + 48 worms
= 96 worms.
Therefore, a robin ate a total of 96 worms last week.