Calculate the number of moles of O2 that would be needed to react with 38.9 moles of C8H18 .
2 C8H18(s) + 25 O2(g) → 16 CO2(g) + 18 H2O(l)
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@ oco shine :)
Exactly. If Valerie didn't understand my explanation I've invited her to explain what she didn't get and we can go from there. But there is no point in explaining another way unless I know the problem.
I'm talking about you bozo.
And spell my name right, jeez.
Srry if I was rude but stop being mean :<
To calculate the number of moles of O2 required to react with 38.9 moles of C8H18, we can use the stoichiometric ratios from the balanced chemical equation.
The stoichiometric ratio between C8H18 and O2 in the balanced equation is 2:25. This means that for every 2 moles of C8H18, we need 25 moles of O2.
First, we can calculate the number of moles of O2 required to react with 38.9 moles of C8H18:
38.9 moles C8H18 × (25 moles O2 / 2 moles C8H18) = 486.25 moles O2
Therefore, 486.25 moles of O2 would be needed to react with 38.9 moles of C8H18.