Which element would most likely lose electrons to form positive ions when bonding with other elements?
A: Gallium (Ga)
B: Rubidium (Rb)
C: Iodine (I)
D: Argon (Ar)
1) rubidium (Rb)
2) The sodium atom transfers electrons to the chlorine atoms to form ionic bonds.
3) nitrogen (N) and oxygen (O)
4) the relative strength with which an element attracts electrons in a chemical bond
5) bromine and nitrogen
rubidium (Rb)
The sodium atom transfers electrons to the chlorine atoms to form ionic bonds.
nitrogen (N) and oxygen (O)
the relative strength with which an element attracts electrons in a chemical bond
bromine and nitrogen
100% correct
no one is 100% correct!!!
@no one. I could kiss you RN ;)
i hate furries is correct tysmmm
BTW @no one is 100000000000% correct
Thank you!
lol how ironic that a furry used a furry haters answers to check theirs and it was 100%
Ga has 31 protons and is a metal in group IIIA of table, forms +3 ion by losing 3 electrons
thank you both
care not
Gallium is a correct answer and for the reason cited.
However, I think Rb is a better answer since the question asks for the "most likely". Rb is far more reactive than Ga. If for no othr reason, Rb has only one electron to lose while Ga has three to lose and the ionization potential for Rb (with one electron) is lower than that of Ga (with three electrons)..