Two numbers differ by 6,the difference of their squares is 120.find the numbers
Help me solve this pls
Let the numbers be x and y
x-y=6,x^2-y^2=120
the solve for x and y
x = y - 6
x^2 - y^2 = (y-6)^2 - y^2 = 120
Solve for y, then x.
Two numbers differ by 6 ,the difference of their square is 120.Find the number
Two numbers differ by 6 ,the difference of their square is 120.Find the number
Two numbers differ by 6 ,the difference of their square is 120.Find the number
y-x=6,y^2-x^2=120.
x=y-6
y^2-(y-6)^2=120
y^2-y^2+6^2=120
y^2-