Find the area bounded by the equation x/- 5 + 2/2 = 1 on the first quadrant and the line x = 10
x/- 5 + 2/2 = 1
I have no idea what this means. Does your keyboard have parentheses?
Find the area bounded by the equation x/(- 5) + y/2 = 1 on the first quadrant and the line x = 10
x over negative 5 plus y over 2
To find the area bounded by the equation \(x/5 + 2/2 = 1\), we can start by rewriting it in the standard form:
\(x/5 + 1 = 1\)
Multiplying both sides by 5, we get:
\(x + 5 = 5\)
Subtracting 5 from both sides gives us:
\(x = 0\)
So, the equation is equivalent to \(x = 0\), which is a vertical line.
To find the area bounded by this vertical line \(x = 0\) and the horizontal line \(x = 10\), we need to calculate the integral of the function \(f(x) = 1\) with respect to \(x\) from 0 to 10.
The area can be calculated using the definite integral:
\(A = \int_{0}^{10} 1 \,dx\)
Evaluating the integral, we get:
\(A = \bigg[x\bigg]_{0}^{10} = \left[10 - 0\right] = 10\)
Therefore, the area bounded by the equation \(x/5 + 2/2 = 1\) in the first quadrant and the line \(x = 10\) is equal to 10 square units.