Check my work please and thank you
4 I^2 + 152 I
P= 8 I + 152 I
8I + 152=0
8I =152
I=19
P(19)=4(19)^2 + 152(19)
P(19) = 1444 + 2888
P(19) =4332 WATTS
Am i correct?
Thank you ...
Sorry the question is
The power generated by an electrical circuit (in watss) as a function of its current I(amperes) is modeled by:
4 I^2 + 152 I
I think you meant
P = 4 I^2 + 152 I
dP/dI = 8I + 152
so you appear to be looking for maximum/minimum power
now, if
8I + 152=0
then I = -19
P(-19)=4(-19)^2 + 152(-19) = -1444
But power cannot be negative, so maybe you meant
P = 4 I^2 - 152 I
you sort it out
Let's check your work step by step:
Given equation: P = 4I^2 + 152I
1. Calculation of P when I = 19:
P(19) = 4(19)^2 + 152(19)
P(19) = 4(361) + 2888
P(19) = 1444 + 2888
P(19) = 4332
2. Calculation of I when P = 0:
8I + 152 = 0
8I = -152
I = -152/8
I = -19
Your calculations are partially correct.
- The value of I you found is correct: I = 19.
- However, the value of P when I = 19 is not correct.
Correcting your previous calculation:
P(19) = 4(19)^2 + 152(19)
P(19) = 4(361) + 2888
P(19) = 1444 + 5504
P(19) = 6948
So, the correct answer is P(19) = 6948 WATTS.
Please double-check your calculations and make sure to substitute the correct values into the equation.