3x-2y=7y=2x-1
Which part of the equations concern you? What is your question?
3 x - 2 y=7y
2 x - 1 = 7 y
????
3 x = 5 y
x = (5/3) y
10/3 y - 1 = 7 y
-1 = 11/3 y
y = -3/11
x = (5/3)y = -5/11
Woops, immediate dumb error
3 x = 9y so x = 3 y
2 x - 1 = 7 y
6 y - 1 = 7 y
y = -1
x = -3
To find the values of x and y that satisfy the given system of equations:
Equation 1: 3x - 2y = 7
Equation 2: y = 2x - 1
We can use the method of substitution or elimination to solve this system. Let's use the method of substitution:
Step 1: Solve Equation 2 for y in terms of x.
From Equation 2, we have:
y = 2x - 1
Step 2: Substitute the expression for y from Step 1 into Equation 1.
Substituting 2x - 1 for y in Equation 1:
3x - 2(2x - 1) = 7
Step 3: Simplify and solve for x.
Expanding and simplifying the equation:
3x - 4x + 2 = 7
-x + 2 = 7
-x = 7 - 2
-x = 5
x = -5 (dividing both sides by -1)
Step 4: Substitute the value of x into Equation 2 to find y.
Using Equation 2:
y = 2(-5) - 1
y = -10 - 1
y = -11
Therefore, the solution to the system of equations is x = -5 and y = -11.