If the diameter of the circle is 12 inches and the height of the triangle is 14 inches which is closest to the area of the figure in square inches
one guess would be
36π + 12*14
depending, of course, on what the heck the figure is!
To find the area of the figure, we need to determine the combined area of the circle and the triangle.
First, let's find the area of the circle. The formula for the area of a circle is A = πr^2, where A is the area and r is the radius. Since we have the diameter (which is twice the radius), we can calculate the radius by dividing the diameter by 2: r = 12 inches / 2 = 6 inches.
The formula for the area of a circle then becomes A = π(6 inches)^2 = 36π square inches.
Next, let's find the area of the triangle. The formula for the area of a triangle is A = 1/2(base × height).
In this case, the base of the triangle is the same as the diameter of the circle, so it is 12 inches. The height of the triangle is given as 14 inches.
Plugging these values into the formula, we get A = 1/2(12 inches × 14 inches) = 84 square inches.
Finally, we can find the combined area of the figure by adding the area of the circle and the area of the triangle: 36π square inches + 84 square inches ≈ 113.1 square inches.
Therefore, the area of the figure is closest to 113.1 square inches.