An object is let to fall from a 93m height. Determine its speed in (m/s) for t=3.1 s
To determine the speed of an object when it falls from a certain height, you can use the equation for free fall motion:
\[ v = u + gt \]
where:
- \( v \) is the final velocity (speed) of the object,
- \( u \) is the initial velocity (which is 0 in this case, as the object is released from rest),
- \( g \) is the acceleration due to gravity (approximately \( 9.8 \, \text{m/s}^2 \)),
- \( t \) is the time taken (3.1 s in this case).
Substituting the known values into the equation, we have:
\[ v = 0 + (9.8 \, \text{m/s}^2) \times 3.1 \, \text{s} \]
Calculating this expression will give us the speed of the object.
To multiply the acceleration due to gravity (\( g \)) by the time (\( t \)), we need to use a calculator or perform the calculation manually as follows:
\[ v = 9.8 \times 3.1 \]
Simplifying this multiplication, we have:
\[ v \approx 30.38 \, \text{m/s} \]
Thus, the speed of the object at \( t = 3.1 \, \text{s} \) is approximately \( 30.38 \, \text{m/s} \).