A line's equation is given in point-slope form:
y- 17 = 3(x-4)
This line's slope is:
A point on this line that is apparent from the given equation is:
It is 5 try it out
y- 17 = 3(x-4)
y = 3x - 12 + 17
y = 3x + 5
this is in the standard y-intercept slope form, so clearly
the slope is 3 and the y-intercept is 5 or (0,5) is one of the billions and
billions of points on this line.
To find the slope of a line given its equation in point-slope form, you need to understand that the coefficient of the x-term represents the slope.
In the given equation y-17 = 3(x-4), you can see that the coefficient of the x-term is 3. Therefore, the slope of this line is 3.
To find a point on this line that is apparent from the given equation, you can simplify the equation to slope-intercept form (y = mx + b), where m represents the slope and b represents the y-intercept.
Let's simplify the given equation:
y - 17 = 3x - 12
y = 3x - 12 + 17
y = 3x + 5
From this simplified equation, we can deduce that the line crosses the y-axis at the point (0, 5). Therefore, the point (0, 5) is a point on this line that is apparent from the given equation.