Point N is on line segment \overline{MO}
MO
. Given MO=3x+6,MO=3x+6, NO=5x,NO=5x, and MN=x,MN=x, determine the numerical length of \overline{NO}.
NO
.
wow - what a lot of repeated gobbledegook!
Since MN+NO = MO, you have
x + 5x = 3x+6
now finish it off
5
2
To determine the numerical length of line segment NO, we need to determine the value of x first.
We know that N is on line segment MO, which means that the sum of lengths MN and NO is equal to MO.
So, we can write the equation:
MN + NO = MO
Substituting the given lengths, we have:
x + (5x) = 3x + 6
Simplifying the equation further:
6x = 3x + 6
Now, let's isolate the variable x:
6x - 3x = 6
3x = 6
Dividing both sides by 3:
x = 2
Now that we have the value of x, we can substitute it back into the expression for NO to find its numerical length.
NO = 5x = 5(2) = 10
Therefore, the numerical length of line segment NO is 10.