Question

A certain biomolecular reaction at 35◦c has an activation energy of 20kjmol^-1. The addition of a catalyst reduces the activation energy by a factor of four. How much faster does the catalysed reaction occur?

Answer 1

I would do this. Given these conditions

ln k = e^-Ea/RT
ln k1 = e^-20,000/8.314*308 = -7.81 k1 = 4.057E-4
ln k2 = e^-5,000/8.314*308 = -1.95 k2 = 0.142
k1 = 4.057E-4
k2 = 0.142
Then k2/k1 = ?