In a parking lot, each row has 3 more parking spaces than the previous row. If the 1st row has 20 spaces, how many spaces will the 15th row have?
From the given ,
a = 20
d = 3
term(15) = a + 14s
put in your data
a + 14 d
To solve this problem, we can use the information given to find a pattern and then use that pattern to determine the number of spaces in the 15th row.
We are told that each row has 3 more parking spaces than the previous row. So, we can start by finding the number of spaces in each row.
Given that the 1st row has 20 spaces, we can write this as:
1st row: 20 spaces
To find the number of spaces in the 2nd row, we add 3 to the number of spaces in the 1st row:
2nd row: 20 + 3 = 23 spaces
To find the number of spaces in the 3rd row, we again add 3 to the number of spaces in the 2nd row:
3rd row: 23 + 3 = 26 spaces
We can continue this pattern for the subsequent rows, adding 3 to the number of spaces in the previous row:
4th row: 26 + 3 = 29 spaces
5th row: 29 + 3 = 32 spaces
6th row: 32 + 3 = 35 spaces
We can see that for each row, we are adding 3 to the previous row's number of spaces.
To find the number of spaces in the 15th row, we need to find the number of spaces in the 14th row and then add 3 to it.
14th row: 35 + 3 = 38 spaces
Therefore, the 15th row will have 38 parking spaces.