Can someone check my work?
(5)/(c-5)+(9)/(c-5)
The answer i got was 14/(c-5)
answers for 6.4 adding and subtracting rational expressions practice are:
1.B
2.C
3.D
4.B
5.D
6.A
7.B
8.B
9.A
10.D
Thank you Soup !!!
Got 100%
I used soups answer and got 100%
Soup is right
please?
1. (5 / c - 5) + (9 / c - 5)
14 / c - 5
2. (5c / 2c + 7) + (c - 28 / 2c + 7)
6c - 28 / 2c + 7
3. (3n + 2 / n + 4) - (n - 6 / n + 4)
2
4. Find the LCD of the pair 1 / 2 ; 4 / x^2
2x^2
5. Find the LCD of the pair 8 / 5b ; 12 / 7b^3c
35b^3c
6. Find the LCD of the pair 3m / m+n ; 3n / m - n
(m+n)(m-n)
7. ( 7 / 3a ) + ( 2 / 5 )
35 + 6a / 15a
correct, since the two fractions have a common denominator.
thank you!
Thanks soup!! Got 100%
1. (5/c-5) + (9/c-5) = (5+9)/(c-5) = 14/(c-5)
2. (5c/2c+7) + (c-28/2c+7) = (5c+c-28)/(2c+7) = (6c-28)/(2c+7)
3. (3n+2/n+4) - (n-6/n+4) = ((3n+2)-(n-6))/n+4 = (3n+2-n+6)/n+4 = 2
4. To find the LCD, we need to factor the denominators. They are already in factor form, so we just need to take the highest power of each factor: LCD = 2 * x^2
5. To find the LCD, we need to factor the denominators. The prime factorization of 5b is just 5 * b, and the prime factorization of 12 is 2^2 * 3. The prime factorization of 7b^3c is just 7 * b^3 * c. So the LCD is 2^2 * 3 * 5 * 7 * b^3 * c = 420b^3c.
6. To find the LCD, we need to factor the denominators. The first denominator is missing a factor of m-n, so the LCD is (m+n)(m-n). The second fraction already has the right denominator, so no change is needed.
7. (7/3a) + (2/5) = (7*5)/(3a*5) + (2*3a)/(5*3a) = (35+6a) / (15a)