the surface of area of a small piston a is 0.01m^2, the surface area of the big piston A is 0.1m^2 and the effort is 150N, calculate the magnitude of the load F?
(a)39N (b) 50N (c) 20N (d) 10N
150 N / .01 m^2 = x N/ 0.1 m^2
x =1500 N
Please I need response
To calculate the magnitude of the load F, we can use the principle of Pascal's law, which states that when pressure is applied to a fluid in a confined space, it is transmitted equally in all directions.
The formula to calculate the force exerted on the larger piston (F) is given by:
F = (A/a) * Effort
Where:
A = surface area of the larger piston
a = surface area of the smaller piston
Effort = force applied on the smaller piston
Given values:
Surface area of the small piston (a) = 0.01 m^2
Surface area of the large piston (A) = 0.1 m^2
Effort = 150 N
Plugging in the values into the formula:
F = (0.1 m^2 / 0.01 m^2) * 150 N
F = 10 * 150 N
F = 1500 N
Therefore, the magnitude of the load F is 1500 N.
None of the provided options match the calculated value, so there may be an error in the given information or options.