If you are playing dodge ball, and there are 24 people, 6 are skills, how would you balance the two teams if the player ratio were 2:3?
2x+3x = 24+6
find x, then you know the numbers
Would that be 6?
I meant skilled not skills
yes, x=6, but that is not the answer to the question.
Can you tell me?
Please someone answer
I already did, when I showed you how to calculate x.
What do you think 2x and 3x represent?
Pay attention, guy.
Read my name
To balance the two teams in dodgeball, you need to distribute the skilled and unskilled players fairly based on the given player ratio of 2:3.
First, calculate the number of skilled players based on the ratio. Since the ratio is 2:3, divide the total number of players (24) into 2 + 3 parts: 2 parts for skilled players and 3 parts for unskilled players.
2 parts out of 2 + 3 parts represent the skilled players, so (2/5) * 24 = 9.6 skilled players are required. However, since you cannot have a fraction of a player, you would round it down to the nearest whole number. Therefore, 9 skilled players are needed.
Next, subtract the number of skilled players from the total number of players to determine the number of unskilled players. So, 24 - 9 = 15 unskilled players.
Now that you know the number of skilled and unskilled players needed, you can divide them into two teams in equal proportions.
One way to do this is to assign the skilled players evenly to both teams. Since you have 9 skilled players, divide it by 2 to get 4 skilled players per team (you may have one extra player, so it can be decided fairly).
Next, assign the remaining unskilled players evenly to both teams. You have 15 unskilled players, divide it by 2 to get 7 unskilled players per team (again, you may have one extra player).
So, the balanced team composition would be:
Team A: 4 skilled players + 7 unskilled players = 11 players
Team B: 5 skilled players + 8 unskilled players = 13 players
Thus, you would have a balanced allocation of players based on the given player ratio.