Napthalene, C10H8 (s) is burned in a bomb calorimeter assembly. A 3.950 g sample of napthalene causes a
temperature increase of 12.67 °C. If the heat of combustion of naphthalene is -5248 kJ/mol, what is the heat
capacity of the bomb calorimeter?
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q = Ccal*delta T where Ccal is the heat capacity of the calorimeter.
Convert 3.950 g to mols. That's mols = g/molar mass = 3.950/128 = 0.0308/
So the sample of naphthalene will produce 0.0308 mols x 5248 kJ/mol = estimated 162 kJ.
162 kJ = Ccal*12.67. Solve for Ccal
I ignored the negative sign of heat combustion because you know that Ccal will be a positive number.