Consider two circular swimming pools. Pool A has a radius of 44 feet, and Pool B has a diameter of 27.02 meters. Complete the description for which pool has a greater circumference. Round to the nearest hundredth for each circumference. 1 foot ≈ 0.305 meters
27.02m * 1ft/0.305m = 88.59 ft
so, what do you think?
To compare the circumferences of Pool A and Pool B, we need to calculate the circumference of each pool using their respective measurements.
Let's start with Pool A. The circumference of a circle can be found using the formula:
C = 2πr
where C is the circumference and r is the radius.
Given that Pool A has a radius of 44 feet, we can calculate its circumference as follows:
C(pool A) = 2 × π × 44
Now, let's calculate the circumference of Pool B. The formula remains the same, but this time we'll need to convert the diameter to radius.
We are given that 1 foot is approximately equal to 0.305 meters. Therefore, the diameter of Pool B in meters is:
27.02 meters ÷ 0.305 ≈ 88.62 feet
To convert this back to radius, we halve the diameter:
R(pool B) = 88.62 ÷ 2 = 44.31 feet
Now we can find the circumference of Pool B:
C(pool B) = 2 × π × 44.31
Evaluate both equations to find the values of C(pool A) and C(pool B). Round the results to the nearest hundredth to compare the circumferences of the two pools.