The pH=8.60 for a 0.016 molar NTD (toluidine) solution. Find Kb of NTD.
Answer is 1.0 * 10^-9
I did the following calculations and ended up with something entirely different from what the answer is.
pH = 8.60
pOH = 5.40
pOH = -log[OH-]
[OH-] = 10^-pOH
[OH] = 3.98 * 10^-6
I then tried to do an ICE table
C7H9N +H2O <-------->C7H10N + OH-
I. 0.016. 0. 0
C. -3.98*10^-6. +3.98*10^-6 +3.98*10^-6
E 0.016. 3.98*10^-6. 3.98*10^-6
(3.98*10^-6)^2/0.016
9.9*10^-10
What did I do wrong?