In a sequence of numbers, a3=21, a4=26, a5=31, a6=36, and a7=41.
Which equation can be used to find the nth term of the sequence, an?
an=7n
an=7n+21
an=5n+21
an=5n+6
arithmetic sequence
d = 5
an = a + 5(n-1)
eg a5 = 31 = a + 5*4 = a + 20
so
a = 11
so
an = 11 + 5(n-1) = 6 + 5 n
the last one
Find the first 4 numbers of the equation for the sequence: an=5n-21
To find the equation for the nth term of the sequence, let's examine the pattern.
The difference between each term is 5, starting from a3. So, we can determine that the equation must involve multiplying n by 5.
To find the initial term, we can subtract the value of a3, which is 21, from the equation.
Thus, the equation that can be used to find the nth term of the sequence is an = 5n + 16.
To find the equation that represents the nth term of the sequence, we need to look for a pattern.
The given sequence starts with a3=21, and each subsequent term increases by 5: a4=26, a5=31, a6=36, a7=41.
We can see that the nth term is increasing by 5n, where n is the position of the term in the sequence. Therefore, the equation that can be used to find the nth term, an, is an = 5n + 16.
Therefore, the correct option would be an=5n+21.