When 9.00 LITERS of NO2react with 7 LITERS of H2O, how many LITERS of NO will be produced at STP ?

OIC

3NO2+ 1H2O ------> 1NO + 2HNO3
How many moles of NO2 in 9 liters at stp?
9 L * 1 mol / 22.4 L = 0.401 mols
If that is liquid water it is about (7 /1000) meters^3
water mass is about 1000 kg/m^3 so about 7 kg = 7000 grams
mol H2O is 2+16 = 18 g /mol
so we have an excess of water, use 0.301 mols NO2
for every 3 liters of NO2 we get ONE liter of NO
so Three