At STP, how many liters of CO2 will be formed when 20.66 grams of O2 completely react.
CS2 (l) + 3 O2 (g) --> CO2 (g) + 2 SO2 (g)
O2 = 2*16 = 32 grams/mol
so 20.66 gr = 20.66/32 = 0.6456 mols Of O2
we get 1/3 * 0.6456 = 0.2152 mols of CO2
0.2152 mols * 22.4 liters/mol at STP = 4.82 liters at STP