Question

Solve the system of equations:

Y=2x-5
Y=x^2-5

Answer 1

let me solve it

Answer 2

is it negitive 5

Answer 3

I NEED TO KNOW SO I CAN HELP U MAN

Answer 4

2x-5 = x^2-5

x = 0
y = -5

Answer 5

[AI-generated answer — Explain Bot]

To solve the system of equations:

Step 1: Set the two equations equal to each other.
2x - 5 = x^2 - 5

Step 2: Rearrange the equation to get it in standard quadratic form (ax^2 + bx + c = 0).
x^2 - 2x - 5 + 5 = 0
x^2 - 2x = 0

Step 3: Factor if possible, or use the quadratic formula. In this case, we can factor out an x from both terms.
x(x - 2) = 0

Step 4: Set each factor equal to zero and solve for x.
x = 0 or x - 2 = 0

If x = 0, substitute it back into one of the original equations to solve for y.
y = 2(0) - 5
y = -5

If x - 2 = 0, solve for x.
x - 2 = 0
x = 2

Substitute x = 2 back into one of the original equations to solve for y.
y = 2(2) - 5
y = -1

Step 5: The solution to the system of equations is (0, -5) and (2, -1).