A body with a mass of 20kg accelerates uniformly in a straight line according to the law,v=10-2t where v is the final velocity after t in seconds,please help.
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A body with a mass of 20 kg accelerates uniformly in a straight line according to the law, v= 10 - 2t where v is the final velocity after t in seconds. Calculate 1. Initial velocity
2. The acceleration of the body.
To find the acceleration of the body, we can differentiate the equation v = 10 - 2t with respect to time (t).
The given equation represents the velocity-time relationship of the body, where v represents the final velocity at time t. The coefficient of t (-2) in the equation represents the acceleration of the body because acceleration is defined as the rate of change of velocity with respect to time.
Differentiating the equation v = 10 - 2t with respect to time, we get:
dv/dt = d(10 - 2t)/dt
dv/dt = -2
Therefore, the acceleration of the body is -2 m/s^2. Please note that the negative sign indicates that the acceleration is in the opposite direction to the positive direction of motion.