Write a molecular, a complete, and a net ionic equation for the following reaction in aqueous solutions. All equations must be balanced.
d. HBr(aq) and K2SO3(aq)
Balanced molecular equation:
2HBr(aq) + K2SO3(aq) ==> 2KBr(aq) + H2SO3(aq)
Balanced complete ionic equation:
2H^+(aq) + 2Br^-(aq) + 2K^+ + [SO3]^2-(aq) ==> 2K^+(aq) +2Br^-(aq) +
H2SO3(aq)
Note: Some may argue that H2SO3 should be written as SO2(aq) + H2O(l) and that H2SO3 doesn't exist but I assume this post is a general chemistry type question.
Net ionic equation:
2H^+(aq) + [SO3]^2-(aq) ==> H2SO3(aq)
To write the molecular, complete, and net ionic equations for the reaction between HBr(aq) and K2SO3(aq), we need to follow a step-by-step process:
Step 1: Identify the compounds and their formulas.
HBr: Hydrobromic acid
K2SO3: Potassium sulfite
Step 2: Write the molecular equation by combining the reactants and showing the products.
HBr(aq) + K2SO3(aq) → KBr(aq) + H2SO3(aq)
Step 3: Balance the equation by ensuring the number of atoms on both sides is equal.
2HBr(aq) + K2SO3(aq) → 2KBr(aq) + H2SO3(aq)
Step 4: Write the complete ionic equation by showing the dissociation of all soluble compounds.
2H+(aq) + 2Br-(aq) + 2K+(aq) + SO3^2-(aq) → 2K+(aq) + 2Br-(aq) + H2SO3(aq)
Step 5: Write the net ionic equation by removing the spectator ions (ions that appear on both sides unchanged).
H+(aq) + SO3^2-(aq) → H2SO3(aq)
Therefore, the molecular equation is:
2HBr(aq) + K2SO3(aq) → 2KBr(aq) + H2SO3(aq)
The complete ionic equation is:
2H+(aq) + 2Br-(aq) + 2K+(aq) + SO3^2-(aq) → 2K+(aq) + 2Br-(aq) + H2SO3(aq)
The net ionic equation is:
H+(aq) + SO3^2-(aq) → H2SO3(aq)
To write the molecular, complete, and net ionic equations for the reaction between HBr(aq) and K2SO3(aq), we first need to identify the reactants and products.
The reactants are HBr(aq) (Hydrobromic acid) and K2SO3(aq) (Potassium sulfite).
The products of the reaction will be formed by the combination of the positive ion from one reactant with the negative ion from the other reactant.
1. Molecular Equation:
In the molecular equation, we write the formulas of the reactants and products without breaking them down into their ions.
HBr(aq) + K2SO3(aq) → 2KBr(aq) + H2SO3(aq)
2. Complete Ionic Equation:
In the complete ionic equation, we separate all soluble ionic compounds into their respective ions.
H+(aq) + Br-(aq) + 2K+(aq) + SO3^(2-)(aq) → 2K+(aq) + Br-(aq) + H2SO3(aq)
Note: HBr(aq) dissociates completely into H+(aq) and Br-(aq), while K2SO3(aq) dissociates into 2K+(aq) and SO3^(2-)(aq).
3. Net Ionic Equation:
In the net ionic equation, we remove the spectator ions, which are ions that appear on both the reactant and product sides of the equation.
H+(aq) + SO3^(2-)(aq) → H2SO3(aq)
Note: The spectator ions (K+ and Br-) are not involved in the actual chemical reaction, so they are removed from the equation.
Finally, all equations should be balanced to ensure the conservation of mass and charge.