The volume of a cup of water increases by 10% when it turns to ice. By how
much does the volume of ice decrease after it melts completely to water again?
9%
i looked it up
1 cup = 236.6 mL
10% increase is 236.6 x 0.1 = 23.66 mL to make the total 260.3 mL as ice.
Whenit melts it goes back to 238.6 which is a difference of 23.66 so as a percentage that is 23.66/260.3 = 0.0908 which I would round to 0.091 and multiply by 100 to get 9.1% decrease.
To find the answer, we need to calculate the decrease in volume when the ice melts completely and turns back into water. Let's break it down step by step:
Step 1: Determine the original volume of the cup of water.
Let's assume the original volume of the cup of water is V.
Step 2: Calculate the volume increase when the water turns into ice.
According to the question, the volume of the cup of water increases by 10% when it turns into ice. So, the volume of ice is V + 0.1V = 1.1V.
Step 3: Determine the volume of water when the ice melts completely.
When the ice melts, it will turn back into water, and its volume will be the same as the original volume of the cup of water, which is V.
Step 4: Calculate the decrease in volume when ice turns back into water.
The decrease in volume can be calculated as the difference between the volume of ice and the volume of water when the ice melts completely.
Decrease in volume = Volume of ice - Volume of water
Decrease in volume = 1.1V - V
Decrease in volume = 0.1V
Therefore, the volume of ice decreases by 0.1V or 10% when it melts completely back into water.