Find the 8 term of an exponential sequence whose first term is 3 and whose common ratio is 2.
nth term = a r^(n-1)
8th term = a r^7 = 3 * 2^7 = 3 * 128 = 384
The 2nd term of an exponential sequence is 9 while the 4th term is 81 find the common ratio , the first term and the sum of first five terms of the sequence.
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Find the 8th term of an exponential sequence whose first term is 3 and whose common ratio is 2
nth term = a x r^(n-1), where a is the first term, r is the common ratio, and n is the term number.
In this case, a = 3 and r = 2. So, the 8th term would be:
8th term = 3 x 2^(8-1) = 3 x 2^7 = 3 x 128 = 384
Therefore, the 8th term of the sequence is 384.