How much heat is required to raise the temperature of 250.0 g of lead by 52°C?
q = mass Pb x specific heat Pb x delta T
q = 250.0 x specific heat Pb x 52 = ?
Post your work if you get stuck.
To calculate the amount of heat required to raise the temperature of a substance, you can use the equation:
q = m * c * ΔT
Where:
q = heat energy (in joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in J/g°C)
ΔT = change in temperature (in °C)
The specific heat capacity of lead is approximately 0.13 J/g°C.
Let's substitute the given values into the equation:
m = 250.0 g
c = 0.13 J/g°C
ΔT = 52°C
q = 250.0 g * 0.13 J/g°C * 52°C
q = 1690 J
Therefore, it requires approximately 1690 joules of heat to raise the temperature of 250.0 g of lead by 52°C.
To determine the amount of heat required to raise the temperature of a substance, you can use the specific heat capacity (C) of the material. The specific heat capacity is the amount of heat energy required to raise the temperature of 1 gram of a substance by 1 degree Celsius.
In this case, you need to find the heat energy (Q) required to raise the temperature of 250.0 g of lead by 52°C. The specific heat capacity of lead is approximately 0.13 J/g°C.
The formula to calculate the heat energy is:
Q = m * C * ΔT
Where:
Q = heat energy (in Joules)
m = mass of the substance (in grams)
C = specific heat capacity (in J/g°C)
ΔT = change in temperature (in °C)
Now we can substitute the given values into the formula:
m = 250.0 g (mass of lead)
C = 0.13 J/g°C (specific heat capacity of lead)
ΔT = 52°C (change in temperature)
Q = 250.0 g * 0.13 J/g°C * 52°C
Calculating this, we get:
Q = 1690 J
Therefore, the amount of heat required to raise the temperature of 250.0 g of lead by 52°C is 1690 Joules.