In a square up is 4y-3,4x+1,y+3x,5y-3x are in cm. Find the x and y and the area
What is the solution
Pls wats the solution
What is the answer
What is the answer
To find the values of x and y in a square, we need to use the given expressions 4y-3, 4x+1, y+3x, and 5y-3x.
In a square, all the sides are equal in length. Therefore, we can equate the given expressions as follows:
4y-3 = 4x+1 ------(1)
4y-3 = y+3x ------(2)
4x+1 = y+3x ------(3)
5y-3x = 4y-3 ------(4)
Let's solve these equations step-by-step:
From equation (3), we can subtract 3x from both sides:
4x + 1 - 3x = y + 3x - 3x
x + 1 = y ------(5)
Now, substitute equation (5) into equations (1) and (2):
Substituting equation (5) into equation (1):
4y - 3 = 4(x + 1)
4y - 3 = 4x + 4
4y = 4x + 7 ------(6)
Substituting equation (5) into equation (2):
4y - 3 = (x + 1) + 3x
4y - 3 = 4x + 1 + 3x
4y = 7x + 4 ------(7)
Now, we can equate equations (6) and (7):
4x + 7 = 7x + 4
Subtract 4x from both sides:
7 - 4 = 7x - 4x
3 = 3x
Divide both sides by 3:
3/3 = 3x/3
1 = x
Now, substitute the value of x into equation (5):
1 + 1 = y
2 = y
So, the value of x is 1 and the value of y is 2.
To find the area of the square, we need to find the length of one side. Let's choose equation (1) for this:
4y-3 = 4x+1
Substituting the values of x and y we found:
4(2)-3 = 4(1)+1
8-3 = 4+1
5 = 5
The length of each side is 5 cm. Therefore, the area of the square can be found by squaring the length of one side:
Area = (side length)^2
Area = 5^2
Area = 25 square cm
y + 3x = 5y - 3x ... 4y = 6x
substituting ... 6x - 3 = 4x + 1 ... 2x = 4
find x , then substitute back to find y
use x and y to find the side length
... then square the length to find the area