Part 1/2
A particle has an initial horizontal velocity of 1.7 m/s and an initial upward velocity of 4.8 m/s. It is then given a horizontal accelera tion of 2.5 m/s^2 and a downward acceleration of 1.5 m/s^2.
What is its speed after 5.4s?
Answer in units of m/s.
Part 2/2
What is the direction of its velocity at this time with respect to the horizontal?
Answer between -180° and +180°.
Answer in units of degrees.
a = 2.5i - 1.5j
v = (2.5t+1.7)i + (-1.5t+4.8)j
Now you can find v(5.4) and the speed is |v|