When you roll two number cubes, what are the odds, in simplest form, in favor of getting two numbers less than 4?
A. 1:3
B. 3:1
C. 1:4
D. 4:1
Is it A or C? I cant remember.
The correct answer is C.
what do you mean, you can't remember? Just work it out.
3 of the six numbers less than 4, so the chance of getting two of them is 3/6 * 3/6 = 1/4
But that makes the odds 1:3
odds are not the same as probability.
I cant remember if i need to subtract the amount of the first thing from the second one or not, sorry for confusion. i just forgot a step so i was confused
To find the odds in favor of an event, we need to determine the number of favorable outcomes and the number of possible outcomes.
In this case, we want to find the odds of rolling two numbers less than 4 when rolling two number cubes.
First, we need to determine the favorable outcomes. Rolling two numbers less than 4 means rolling either a 1, 2, or 3 on each die.
For the first die, there are three favorable outcomes: 1, 2, and 3.
Similarly, for the second die, there are also three favorable outcomes: 1, 2, and 3.
To find the total number of possible outcomes, we need to consider the number of choices for each die. Since each die has six sides numbered from 1 to 6, there are 6 x 6 = 36 possible outcomes.
Therefore, the odds in favor of getting two numbers less than 4 are 3:36, which simplifies to 1:12.
So, the correct answer is not A or C. The correct answer is:
A. 1:12