Construct a ABC in which AB=AC=5.2cm and angle A=120degree draw AD perpendicular BC
so, what's the trouble?
I assume you can construct 60- and 90-degree angles, right?
To construct an ABC triangle with AB = AC = 5.2 cm and angle A = 120 degrees, follow these steps:
1. Start by drawing a straight line segment and label it AB with a length of 5.2 cm.
-------------- A ------------------------- B ---------------
2. Using a compass, place the needle at point A and draw an arc with a radius of 5.2 cm to intersect the line AB. Label this point as C.
-------------- A ------------------------- B ----------
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C
3. With the compass still set at a radius of 5.2 cm, place the needle at point C and draw another arc to intersect the previous arc. Label this point as D.
-------------- A ------------------------- B ----------
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C
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D
4. Draw the line segment CD to connect points C and D. This line should be perpendicular to AB.
-------------- A ------------------------- B ----------
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C
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D
5. Finally, draw the line segments AD and BD to complete the triangle ABC.
-------------- A ------------------------- B ----------
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C
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D
To construct a triangle ABC with AB = AC = 5.2 cm and angle A = 120 degrees, and AD being perpendicular to BC, you can follow the steps below:
1. Start by drawing a straight line segment XY of any length. This will serve as the base for Triangle ABC.
2. With X as the starting point, measure a distance of 5.2 cm and mark a point as A on the line XY.
3. From point A, use a compass to draw arcs on both sides of A, intersecting the line XY at points B and C, respectively. These points will be used to form the equal sides of the triangle.
4. To draw the angle of 120 degrees at point A, use a protractor. Place the protractor with its center on point A and align the baseline with line XY. Mark two points on each side of the protractor at an angle of 120 degrees. Connect the points, creating a line that intersects line XY at point D.
5. Finally, draw a perpendicular line from point D to line BC. This can be done using a compass. Place the compass at point D and adjust its width to reach across line BC. Draw two arcs above and below line BC, intersecting at points E and F, respectively. Connect points E and F to point D, creating a perpendicular line.
Now you have successfully constructed Triangle ABC, where AB = AC = 5.2 cm, angle A = 120 degrees, and AD is perpendicular to BC.