A meter rule is from to balance at 51cm Mark when a body of mass 70g is suspended at 10cm mark the balance point is frame to be at 25cm marks. find;
The distance of the balance point of zero end if the body where move to the 20cm marks
To solve this problem, we can use the principle of moments. The principle of moments states that for an object to be in equilibrium, the sum of the moments acting on it must be zero.
The moment of a force is given by the product of the force and the perpendicular distance from the point of rotation (or fulcrum) to the line of action of the force.
Let's break down the given information:
- When a body of mass 70g is suspended at the 10cm mark, the balance point is at the 25cm mark.
- We want to find the new balance point when the body is moved to the 20cm mark.
We can start by calculating the moment of the body at the 10cm mark. We have:
Moment1 = (Distance1) x (Mass1)
= (51cm - 10cm) x (70g)
= 41cm x 70g
= 2870 g.cm^2 (gram-centimeter squares)
According to the principle of moments, this moment should be equal to the moment of the body at the new balance point, when it is moved to the 20cm mark. Let's call this unknown distance X.
Moment1 = Moment2
2870 g.cm^2 = (Distance2) x (Mass1)
2870 g.cm^2 = (X + 20cm) x (70g)
To isolate X, divide both sides of the equation by 70g:
2870/70 = X + 20
Now, subtract 20 from both sides of the equation to solve for X:
41 = X
Therefore, the distance of the balance point from the zero end if the body is moved to the 20cm mark is 41cm.