I just need a little bit of help with math homework so please respond ASAP if you know what it is!
Triangle ABC has coordinates A(2, 3), B(-3, 4), and C(5, 7). The triangle is being dilated from the origin with a scale factor r=4. What are the coordinates of triangle A’B’C’ ?
just multiply all the coordinates by 4
A' , B' , and C' are four times the distance from the origin as A , B , and C
eg. A' = [(2 * 4),(3 * 4)]
To find the coordinates of the triangle A'B'C', we need to apply the dilation transformation on each vertex of the original triangle.
First, let's find the coordinates of A':
To dilate a point from the origin, we multiply the coordinates of the point by the scale factor. In this case, the scale factor is 4.
So, for point A(2, 3), we multiply the x-coordinate and y-coordinate by 4:
New x-coordinate of A' = 2 * 4 = 8
New y-coordinate of A' = 3 * 4 = 12
Therefore, A' has coordinates (8, 12).
Next, let's find the coordinates of B':
For point B(-3, 4), we multiply the x-coordinate and y-coordinate by 4:
New x-coordinate of B' = -3 * 4 = -12
New y-coordinate of B' = 4 * 4 = 16
Therefore, B' has coordinates (-12, 16).
Finally, let's find the coordinates of C':
For point C(5, 7), we multiply the x-coordinate and y-coordinate by 4:
New x-coordinate of C' = 5 * 4 = 20
New y-coordinate of C' = 7 * 4 = 28
Therefore, C' has coordinates (20, 28).
In conclusion, the coordinates of triangle A'B'C' are A'(8, 12), B'(-12, 16), and C'(20, 28).