Hi beautiful people! i need help with a question.
Write the equation in point-slope form of a line that goes through (-3,4) with slope 7.
can someone pls help me out.
In this case:
m = 7 , x = - 3 , y = 4
Point-slope form of a line:
y = m ∙ x + b
Replace m = 7 , x = - 3 , y = 4 in this equation.
4 = 7 ∙ ( - 3 ) + b
4 = - 21 + b
Add 21 to both sides
25 = b
b = 25
y = m ∙ x + b
y = 7 x + 25
Ohhh, thank you very much that helped me.
point-slope form
the line through (h,k) with slope m is
y-k = m(x-h)
So your line is
y-4 = 7(x+3)
Of course! I'd be happy to help you with that.
To write the equation in point-slope form, you need to use the formula:
y - y1 = m(x - x1)
where (x1, y1) is a point on the line, and m is the slope.
In this case, the point (-3, 4) lies on the line, and the slope is 7.
Plugging these values into the formula, we get:
y - 4 = 7(x - (-3))
Simplifying the equation, we have:
y - 4 = 7(x + 3)
Now, you can distribute the 7 to both terms inside the parentheses:
y - 4 = 7x + 21
Finally, you can add 4 to both sides to isolate the term with y:
y = 7x + 25
So, the equation in point-slope form of the line that goes through (-3, 4) with slope 7 is y = 7x + 25.