√((4x+1)/(x+3)) - √((x-2)/(x+3)) = 1 clearing the fractions, we have √(4x+1) - √(x-2) = √(x+3) now square both sides to get 4x+1 - 2√((4x+1)(x-2)) + x-2 = x+3 √((4x+1)(x-2)) = 2x-2 (4x+1)(x-2) = 4(x^2-2x+1) 4x^2 - 7x - 2 = 4x^2 - 8x + 4 x = 6 check: √(25/9) - √(4/9) = 5/3 - 2/3 = 1
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