-6(y+15)=-3y+6 what value of y makes the equation true?
-6(y+15)=-3y+6
-6y - 90 = -3y + 6
3y = -84
y = -28
Someone, if you want to help, that's great.
But make sure you are correct.
You can start with spelling: there's, not theirs...
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To find the value of y that makes the equation true, we need to solve for y. Let's start by simplifying the equation step by step.
Given equation: -6(y+15) = -3y+6
1. Distribute the -6 to both terms inside the parentheses:
-6y - 6(15) = -3y + 6
-6y - 90 = -3y + 6
2. Combine like terms.
Since we have -6y and -3y on the right side, we can simplify it by adding 3y to both sides of the equation:
-6y + 3y - 90 = -3y + 3y + 6
-3y - 90 = 6
3. Simplify further.
Now, we can simplify by adding 90 to both sides of the equation to isolate the variable on one side:
-3y - 90 + 90 = 6 + 90
-3y = 96
4. Divide both sides of the equation by -3 to solve for y:
(-3y)/-3 = 96/-3
y = -32
Therefore, the value of y that makes the equation true is y = -32.
it is the fact that it is in the negitive form
and that the +15 is sstill also true