Find the digit that makes _1,258 divisible by 9. also 19 is a diy answer :(
11,258/9 = 1250.88888888
21,258/9 = 2,362 the end
read up on casting out nines. The sum of the digits must be a multiple of 9, so since 1+2+5+8 = 16, the missing digit is 2
21258 = 9*2362
To determine the digit that makes the number _1,258 divisible by 9, we need to calculate the sum of its digits and find out what digit should be in the placeholder.
The sum of the digits in _1,258 is:
1 + 2 + 5 + 8 = 16
To make it divisible by 9, we need to find a digit to replace the underscore (_) that will result in a multiple of 9 when added to the sum.
Let's consider the numbers from 0 to 9. If we add any single digit to the sum (16), we will obtain a number between 17 and 25.
The only digit that will make the sum a multiple of 9 is 1.
Therefore, the digit that makes _1,258 divisible by 9 is 1.
To find the digit that makes 1,258 divisible by 9, we need to calculate the sum of its digits and see which number, when added to the sum, will make it divisible by 9.
First, let's find the sum of the digits in 1,258:
1 + 2 + 5 + 8 = 16.
To make 1,258 divisible by 9, we need to find a digit that, when added to the sum of the digits (16), will result in a multiple of 9. In other words, we want the remainder when the sum is divided by 9 to be equal to 0.
To accomplish this, we can start by finding the remainder of 16 divided by 9:
16 % 9 = 7.
Since the remainder is not 0, we need to find the difference between the next multiple of 9 and the remainder:
9 - 7 = 2.
Therefore, the digit that needs to be added to 1,258 to make it divisible by 9 is 2.
The number 19 mentioned in your question is not related to finding the digit that makes 1,258 divisible by 9; it seems to be a separate answer or piece of information. If you have any further questions or if there's anything else I can assist you with, please let me know!