A football is kicked at a velocity of 15 m/s at an angle of 25 to the horizontal.calculate;
calculate what?
Good
15 and 25°
To calculate the horizontal and vertical components of the velocity, we can use trigonometry.
The horizontal component of the velocity can be found using the equation:
Vx = V * cos(θ)
where Vx is the horizontal component of the velocity, V is the magnitude of the velocity (15 m/s), and θ is the angle with respect to the horizontal (25 degrees).
Vx = 15 * cos(25)
Vx ≈ 13.57 m/s
The vertical component of the velocity can be found using the equation:
Vy = V * sin(θ)
where Vy is the vertical component of the velocity.
Vy = 15 * sin(25)
Vy ≈ 6.35 m/s
Now, we have the horizontal and vertical components of the velocity.