h = −4.9t2 + 29.4t + 1.9,
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Online "^" is used to indicate an exponent, e.g., x^2 = x squared.
The equation you provided is a quadratic equation in the form of h = -4.9t^2 + 29.4t + 1.9, where h represents height and t represents time.
To understand this equation, it helps to know that it represents the height of an object in free fall when air resistance is negligible. The equation is derived from the physics formula for the vertical position of an object in free fall, which is given as h = -1/2gt^2 + vt + h0.
In this equation, -1/2gt^2 represents the gravitational acceleration pulling the object downward, where g is approximately 9.8 m/s^2 (acceleration due to gravity) and t^2 represents the time squared. vt represents the initial velocity multiplied by time, where v is the initial velocity (velocity at t = 0) of the object. h0 represents the initial height (height at t = 0) of the object.
Comparing both equations, we can see that the values of -1/2g and v have been replaced by the coefficient of t^2 (-4.9) and the coefficient of t (29.4) respectively. The constant term (1.9) represents the initial height in this case.
So, in the given equation h = -4.9t^2 + 29.4t + 1.9, the coefficient of t^2 (-4.9) represents half of the gravitational acceleration, the coefficient of t (29.4) represents the initial velocity, and the constant term (1.9) represents the initial height.
If you have a specific question related to this equation, please let me know and I'll be happy to help further!